Get date from filename

icy_blu_blu · #1 (**permalink**) 07-15-2008

Hi all,
I have this files:
aaa20080714.log
bbbb20080714.log
ccccccc20080714.log

Can i get the 20080714 from each file?

zaxxon · #2 (**permalink**) 07-15-2008

Code:

sed 's/^[a-z]*\([0-9]*\).log/\1/g' infile
20080714
20080714
20080714

ghostdog74 · #3 (**permalink**) 07-15-2008

ls *.log | awk -v d=$(date +%Y) -F"." '{ pat=".*"d; gsub(pat,"",$1);print d$1}'

vbe · #4 (**permalink**) 07-15-2008

Just for the fun, and to give a good reason why one should learn awk and sed to survive in shell scripting:

ant:/tmp $ ll ccc*
-rw-r--r-- 1 vbe sys 0 Jul 15 15:26 ccccccc20080714.log
ant:/tmp $ ls|grep ccc*.log|cut -c$(echo $(expr $(ls|grep ccc*.log|wc -c) - 12)"-"$(expr $(ls|grep ccc*.log|wc -c) - 5))
20080714

jim mcnamara · #5 (**permalink**) 07-15-2008

Or... try tr

Code:

echo aaa20080714.log| tr -dc '[:digit:]'
# if the filenames are in a file
tr -dc '[:digit:]'  < infile

sudhamacs · #6 (**permalink**) 07-15-2008

ls *.log | awk -F'.' '{print substr($1,length($1)-7)}'

icy_blu_blu · #7 (**permalink**) 07-15-2008

It's working, thanks alot guys.
I'm just learning awk & sed and got this trouble. Gonna dig deeper.

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