nested loop problem

mmunir · #1 (**permalink**) 07-04-2008

Please see the following script.

basic="a b c"
advance="d e f"

A="basic advance"

for g in $A
do
echo $g
done

The result would be obviously
basic
advance

I want to ask how can i get the following result using $A in for loop
a
b
c
d
e
f

zaxxon · #2 (**permalink**) 07-04-2008

Code:

basic="a b c"
advance="d e f"
A="${basic} ${advance}"
for g in $A; do
     echo $g
done

mmunir · #3 (**permalink**) 07-04-2008

Thanks for reply!

The problem is that

The following statement has already been defined in a file and i cannot change it.

A="basic advance"

To change it into your style, i would do

A=`echo $A | sed -e s/' '/'} \${'/g`
A="\${${A}"

but when i run
echo $A

i get:

${basic} ${advance}

which is not the desired result

zaxxon · #4 (**permalink**) 07-04-2008

Code:

root@isau02:/data/tmp/testfeld> cat weekend.ksh
basic="a b c"
advance="d e f"
A="basic advance"

for ele in ${A}; do
        eval echo $`echo $ele`
done |\
tr -s " " "\n"

exit 0
root@isau02:/data/tmp/testfeld> ./weekend.ksh
a
b
c
d
e
f

namishtiwari · #5 (**permalink**) 07-04-2008

Give a try

Code:

for value in 'a b c d e f'
  do
     echo $value
  done

Annihilannic · #6 (**permalink**) 07-04-2008

Code:

basic="a b c"
advance="d e f"

A="basic advance"

for g in $A
do
    eval echo \$$g
done

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