Hi All,
Please help me in solving this. How can I find the date time, given seconds in number from date 01/01/2002. Using K shell
or C program

Example if I have 3600 (seconds) I should get the output as
01/01/2002 1:00:00 am


Thanks in advance
Krishna

You might find your answer using Perderabo's datecalc script found here

datecalc is a start, but it only handles dates, not time. This script should do the trick...

#! /usr/bin/ksh

        integer inputsecs days daysecond hoursecond
        typeset -Z2 month day hour minute second

        inputsecs=$1

        ((days=inputsecs/86400))
        ((daysecond=inputsecs%86400))
        ((hour=daysecond/3600))
        ((hoursecond=daysecond-(hour*3600)))
        ((minute=hoursecond/60))
        ((second=hoursecond%60))

        datecalc -a 2001 1 1 + $days | read year month day

        if((hour < 12)) ; then
                p="am"
        else 
                ((hour=hour-12))
                p="pm"
        fi
        ((hour == 0)) && ((hour=12))

        time="$month/$day/$year ${hour}:${minute}:${second} $p"
        echo "$time"
exit 0

Thanks for the code .
Do you have a C program to do this. Code in K Shell looks complicated to me. I do not use much of K Shell. I better use C program

Thanks once again
Krishna

Sorry, I don't have this in C.

Thanks for your help