Print lines after grep

jakSun8 · #1 (**permalink**) 06-25-2008

Hi all,

I need help in following scenario. I have a file with about 10,000 lines. There are several lines which have word "START" (all upper case) in them. I want to grep line with word "START" and then do the following
1. Print the line number having word "START"
2. Print the next 11 lines.

Any help is appreciated.
JAK

danmero · #2 (**permalink**) 06-25-2008

Code:

awk '/START/{f=NR;print NR}{if(NR > f && NR < f+12) print}' data.file

radoulov · #3 (**permalink**) 06-25-2008

Another one:

Code:

awk 'c&&c--;/START/{print NR;c=11}' file

danmero · #4 (**permalink**) 06-25-2008

Quote:

Originally Posted by radoulov

Code:

awk 'c&&c--;/START/{print NR;c=11}' file

That's nice

jakSun8 · #5 (**permalink**) 06-25-2008

Thanks for the reply. I really appreciate it.

JAK

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