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05-30-2008
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Regular expression
Hi
I have to extract the first field and the last %field of the following out put.. /home (/abc/def/bhd ) : 522328 total allocated Kb 319448 free allocated Kb 202880 used allocated Kb 38 % allocation used i need to to get only /home and 38% allocation used in a array. How to do it in a perl script using sed or awk or regular expression. Regards... Last edited by Harikrishna; 05-30-2008 at 11:02 AM.. |
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05-31-2008
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In seperate lines: Code:
awk 'NR==1{print $1}END{print}'
In one line: Code:
awk 'NR==1{printf("%s ",$1)}END{print}'
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