Hi
i am having a file of more than 60,000 lines.

need to grep a string and write the line of string and next line of the grepped string

any suggestions

From man grep:

OPTIONS
       -A NUM, --after-context=NUM
              Print  NUM  lines  of  trailing  context  after  matching lines.
              Places  a  line  containing  --  between  contiguous  groups  of
              matches.

If you don't have GNU grep you could use sed:

sed -n '/pattern/{N;p;}' input

using awk,

awk ' $0 ~ /search_string/ { print ; t=1 ; next }
t==1{print;t=0}' file_name

Thanks
Penchal

Or:

awk '_&&_--;/pattern/{_=2}' input

Hi radoulov,

your command outputs 2 lines after the grepped string. How to get the grep string line and next line

Oops, sorry, it should be:

awk '/pattern/{_=2}_&&_--' input