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05-17-2008
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String substitution on find results inside exec/xargs
What I'm trying to do is perform a copy, well a ditto actually, on the results of a find command, but some inline string substitution needs to happen.
So if I run this code Code:
find ./ -name "*.tif" .//1234567.tif .//abcdefg.tif Now the action from exec or xargs I want would be these two things.... ditto .//1234567.tif /some/path/1/2/3/ ditto .//abcdefg.tif /some/path/a/b/c/ So as you can see it's taking the first three characters from each found result and using those to construct a path. Any ideas I'm sure this can be done easier in a actual script, but i need to keep this as an actual "one line" command. Any ideas? 
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05-17-2008
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Code:
find . -name '*.tif' | sed -e 's%\(.//*\)\(.\)\(.\)\(.\)\(.*\)%ditto \1\2\3\4\5 /some/path/\2/\3/\4/%' | sh Last edited by era; 05-17-2008 at 05:56 AM. Reason: Optionally allow more than one slash
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