I need to rename a directory in every home directory on a given workstation. I am a newb to scripting so maybe thats why I cant exactly figure out how to correctly do this.

The first thing I need to be able to do to write this script is figure out how to list all the directorys (these are not actual home directorys).

Im using solaris so that may complicate things for me.

ls -d only lists "." so that command is worthless.. for this.

find /path/to/users -type d ; somewhat works but it also lists every directory past users. I cant seem to find a way to tell it to only look in the one directory.the output is the following:

/path/to/user1
/path/to/user1/dir1
/path/to/user1/dir2
/path/to/user2/
/path/to/user2/dir1
/path/to/user2/dir2

I need to only see /path/to/user1 and /path/to/user2.

Anyone have any ideas on else I could try? Also, if it matters, Im using solaris to work on/write this script.. but the actual script will be for OSX, a post install script for an application upgrade.

edited for a little more info.

To list all the directories ,

In solaris , u can use dir command.

Even u can use this : ls -ltr | grep "^d"

Thanks
Penchal

awesome penchal!

ls -ltr | grep "^d" | cut -c55-75

will work! Ill see if I can get what I want with dir without having to crep and cut as well

edit: On second though.. is there a way to just print everything from the 55 characters spot to the last character on the line? I think my variables with cut -c55-75 would include spaces tailed at the end? Im thinking tr could be used to do that.. but it would just make the command that much longer?

ls -ltr | grep "^d" | cut -c55-75 | tr -d ' '

??? Is that too long of a command to throw in a script as a vairable? I dont think so.. but im still newbish to this