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05-13-2008
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How to parse a string efficiently
I am new to the boards and to shell programming and have a requirement to name new files received with a unique sequence number. I need to look at a particular file pattern that exists and then to increment a sequence by 1 and write the new file.
Example of file names and sequence # part1_part2_part3_datesequence.dat or part1_part2_part3_part4_datesequence.dat the sequence is a 6 digit right justified 0 filled number attached to the date - 20080501000001.dat, but may be the 4th, 5th, 6th or 7th token of the filename. I have a script that creates the new files, but I am having trouble with how to efficiently extract the sequence number in order to increment it by 1 for a given file pattern and date and then write the new file. Any help would be appreciated and I am trying to stay with shell or sed or awk as I do not have access to perl. thanks! Mike 
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05-13-2008
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one way:
Code:
#!bin/ksh
file="20080501000001.dat"
echo ${file%%.dat} | read seq
len=`expr length $seq`
let start=$len-14
seq=`expr $seq $start 14`
typeset -i num
echo ${seq##????????} | read num
echo $num
Last edited by jim mcnamara : 05-13-2008 at 07:49 AM.
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05-13-2008
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Jim,
Exactly what I needed - thanks!
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05-13-2008
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Jim
Could you please breakdown how this works? I am changing up how I return the filenames and it is now not working. I am using an ls -a and get a fully qualified path, but your code above does not seem to handle this. Thanks! Mike
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05-13-2008
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I just used your example filenames.
Code:
# this line was file="20080501000001.dat" ls -rt part1_*`date "+%Y%m%d`*.dat | tail -1 read file Assuming I got your requirements.
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