[csh] How to capture output from a command and pass it on to a variable? - Shell Programming and Scripting

machinogodzilla · #1 (**permalink**) 05-11-2008

Hi there!

I'm trying to write a script that will capture output from a command and assign it to a variable.

Let's say, for example, I'd like to catch from inside the script whatever the following command outputs:

Code:

ls *.aaa

and put it into a variable "listoffiles".

What I tried was:

Code:

set listoffiles = 'ls *.aaa'
echo $listoffiles

and what I got echoed was:

Code:

$ ls file1.aaa file2.aaa file3.aaa

instead of

Code:

$ file1.aaa file2.aaa file3.aaa

I played with this for a while trying various combinations and also looked into a few publications on scripting and couldn't find the solution. What am I doing wrong?

JCR · #2 (**permalink**) 05-11-2008

try using the backtick `
listfiles=`ls *.aaa`

redhead · #3 (**permalink**) 05-11-2008

have you tried:

Code:

set listoffiles = '*.aaa'
echo $listoffiles

machinogodzilla · #4 (**permalink**) 05-11-2008

I can't believe that!

With the backtick it worked just fine!

I need to use the assignment with a different command, this was just an example.

Thank you both for your help!

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