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05-08-2008
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Compare File Names in Different Directories...
I do not know much about shell scripting and need to create a script and I am at a loss. If someone can help me, that would be great!!
I have two directories: /dir1 /dir2 I need to get the sequence number which is part of the filename in /dir1 and delete all files in /dir2 that are less than that sequence number and have the same ending number extension. Example: /dir1/1_400_123456 /dir2/1_400_123456 /dir2/1_399_123456 /dir2/1_398_123456 /dir2/1_300_999999 So, I would need to look in the /dir1 directory and see the sequence number is 400. Then, in the dir2 directory, I need to delete any files that are less than 400 and have the same '123456' ending number. So the only files in /dir2 left would be: /dir2/1_400_123456 /dir2/1_300_999999 Thanks in advance if you can help in anyway! 
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05-08-2008
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Try this script, if you get the expected output you can pipe the output to sh to remove the files.
Code:
#!/bin/sh
cd /dir2
ls /dir1 > tmp1
ls /dir2 > tmp2
awk 'BEGIN {FS=OFS="_"}
NR==FNR{a[$3]=$2;next}
$3 in a{if(a[$3]<=$2){next}}
{print "rm "$0}
' tmp1 tmp2
rm tmp1 tmp2
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05-09-2008
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Thanks for your help! It looks like this is almost there. It is listing all of the files that have a sequence number lower than what is found in the first directory. But, it looks like it is not comparing the next node of the file:
/dir1/1_400_123456 /dir2/1_400_123456 /dir2/1_399_123456 /dir2/1_398_123456 /dir2/1_300_999999 The script is listing: /dir2/1_399_123456 /dir2/1_398_123456 /dir2/1_300_999999 Even though the second node of the file is lower in the /dir2/1_300_999999 file, it should not delete this file because the next node is different.
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05-09-2008
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I looked over something, try this:
Code:
#!/bin/sh
cd /dir2
ls /dir1 > tmp1
ls /dir2 > tmp2
awk 'BEGIN {FS=OFS="_"}
NR==FNR{a[$3]=$2;next}
$3 in a{if(a[$3]>$2){print "rm "$0}
' tmp1 tmp2
rm tmp1 tmp2
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