How to get 07 while giving ((Preyy = yy - 01)) - Shell Programming and Scripting

RRVARMA · #1 05-08-2008

Hi,

I need to get the previous year as 07 instead of just 7. I'm running the following for this..

yy=`date '+%y'`
((Preyy = yy - 01))
echo ${Preyy}

Here, instead of 07 i'm getting 7 as result. Please Help.

Thanks,
RRVARMA

RRVARMA · #2 05-08-2008

i just added this in between...

Preyy=$(printf "%02d" $Preyy)

and now my script goes lik this..

yy=`date '+%y'`
((Preyy = yy - 01))
Preyy=$(printf "%02d" $Preyy)
echo ${Preyy}

Thanks,
RRVARMA

namishtiwari · #3 05-08-2008

Quote:

Originally Posted by RRVARMA

Hi,

I need to get the previous year as 07 instead of just 7. I'm running the following for this..

yy=`date '+%y'`
((Preyy = yy - 01))
echo ${Preyy}

Here, instead of 07 i'm getting 7 as result. Please Help.

Thanks,
RRVARMA

Code:

#!/usr/bin/ksh
yy=`date '+%y'`
prev=0$(( yy - 1 ))
echo $prev

aju_kup · #4 05-08-2008

Best way to do this

Code:

typeset -R2Z Preyy

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