Grep date from ls -l

GenMen · #1 (**permalink**) 05-01-2008

I have a script which required the month and day as the input

ex : ./script <Month> <date>

from this I get the list of files to do further logics. The problem is when I assign these $1 and $2 to variables, and use grep command in the script

ls -l |grep "$1 $2"

it works fine for two digit dates, but for single digit dates, it doesnt work as Unix leaves an additional space in the ls -l list..

How can get this done.

Annihilannic · #2 (**permalink**) 05-01-2008

* will match any number of the preceding character. Also it's good to match a space after the last value so that you don't find Apr 22 when you are actually searching for Apr 2, for example.

Code:

ls -l |grep " $1  *$2 "

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