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04-29-2008
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To find the time difference between two lines of the same log file
Hello Friends,
I want to write a script for the following: nlscux62:tibprod> grep "2008 Apr 30 01:" SA_EHV_SPEED_SFC_IN_03-SA_EHV_SPEED_SFC_IN_03-2.log | grep -i post | more 2008 Apr 30 01:01:23:928 GMT +2 SAPAdapter.SA_EHV_SPEED_SFC_IN_03-SA_EHV_SPEED_SFC_IN_03-2 Info [Adapter] AER3-000095 IDOC posted to client SA_EHV_SPEED_SFC_IN_03InboundConnection4Client0 successfully tracking=#QrQ--5--G/SbkkvU67u6Ucw38-6gQ# 2008 Apr 30 01:01:23:958 GMT +2 SAPAdapter.SA_EHV_SPEED_SFC_IN_03-SA_EHV_SPEED_SFC_IN_03-2 Info [Adapter] AER3-000094 Posting IDOC t o client SA_EHV_SPEED_SFC_IN_03InboundConnection8Client0 tracking=#I0Y--/--G/Sbl-rs68EEcJI5X-mrY# 2008 Apr 30 01:01:24:788 GMT +2 SAPAdapter.SA_EHV_SPEED_SFC_IN_03-SA_EHV_SPEED_SFC_IN_03-2 Info [Adapter] AER3-000095 IDOC posted to client SA_EHV_SPEED_SFC_IN_03InboundConnection8Client0 successfully tracking=#I0Y--/--G/Sbl-rs68EEcJI5X-mrY# On using the above command I can view the time difference between posting and posted. I want that the UNIX program to check for the time difference greater than 1 second. Please help me in this. I am absolutely new to the UNIX environment and know little regarding Shell programming. Hence I would like to have the full code. Thanks |
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