I am pretty new to the Unix word, and have created a working calculator script. I have one problem. It doesn't use any decimals, it rounds off to the nearest whole number.

1 #!/bin/ksh
2 while true; do
3 echo -n "Enter the first integer: "; read IN1
4 test "$OP1" = "x" && exit 0
5 echo -n "Enter an operator: "; read OPR
6 test "$OPR" = "x" && exit 0
7 echo -n "Enter the second integer: "; read IN2
8 test "$OP2" = "x" && exit 0
9 RES=$(expr "$IN1" "$OPR" "$IN2")
10 echo "Answer: $IN1 $OPR $IN2 = $RES";
11 done;

Any ideas? Thanks.

Shell arithmetic is integers only, sorry.

Since Bash only recognizes normal integers, you can pipe the math through the 'bc' utility and it'll return float values.

RES=$(echo "$IN1" "$OPR" "$IN2" | bc)

Hope this helps.