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  #1 (permalink)  
Old 04-24-2008
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Join Date: May 2005
Posts: 190
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exclude a line

Hi,
thanks for your help. I wrote this script :
Code:
# ! /bin/sh
file=snapshot.txt
cat $file | while read line ;
do
{
myvariable=`grep "Nombre de ROLLBACK internes" |sed 's/.*.=//'`
echo $myvariable
}
done
It looks in a file "snapshot.txt" for the lines containing "Nombre de ROLLBACK internes". But there are two lines containing this :
Nombre de ROLLBACK internes = 0
Nombre de ROLLBACK internes dus à interblocages = 7

How can I exclude the following line :
Nombre de ROLLBACK internes dus à interblocages = 7


This my snapshot.txt file :
Code:
Num. de partition de base de données du catalogue       = 0
Nom du catalogue du noeud réseau                        =
Syst. d'exploitation serveur de base de données         = NT
Nombre de ROLLBACK internes = 0
Nombre de ROLLBACK internes dus à interblocages = 7
Emplacement de la base de données                       = Local
Horodatage de la première connexion à la base     = 18.04.2008 05:31:56.832765
Regards.
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  #2 (permalink)  
Old 04-24-2008
...@...
 

Join Date: Feb 2004
Location: NM
Posts: 3,841
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one way
Code:
myvariable=`grep "Nombre de ROLLBACK internes" | grep -v "dus à interblocages" | sed 's/.*.=//'`
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  #3 (permalink)  
Old 04-24-2008
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Join Date: Feb 2007
Posts: 1,953
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Some possibilties:

Code:
grep 'Nombre de ROLLBACK internes =' snapshot.txt |cut -d" " -f6

awk '/^Nombre de ROLLBACK internes =/{print $6}' snapshot.txt

sed '/^Nombre de ROLLBACK internes = /s/.*= //' snapshot.txt
Regards
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  #4 (permalink)  
Old 04-24-2008
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Join Date: May 2005
Posts: 190
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thank you.
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