How to get lines in between Patterns?

racbern · #1 (**permalink**) 04-23-2008

Hi,

I need to create a script that does the following:

1. Read the file for the occurrences of "EXECUTE" and "END" strings.
There will be several occurrences of EXECUTE and END strings on the file.
2. The resulting lines in #1, needs to be searched for the word "Error|failed|error|warning", if the word error occurs on the line, prints the specific line and 1 line above it.

Here's a sample input file:

HTML Code:

-------------------------------< EXECUTE >----------------------------
This session consists of:  Feature  R-state        Install-type Upgrade-from

------------------------------------------------------------------------  
conf_system                              R3C01          upgrade      R3B03     
------------------------------------------------------------------------
------------------< CIF(conf) 2008-04-08 02:31:28 >--------------------
----------------------< END 2008-04-08 02:31:57 >---------------------

-------------------------------< EXECUTE >-----------------------------
---------< FM(fm_core,fmba,fmaa,fmx,fmav) 2008-04-08 03:14:09 >-------
[main] Error installing feature [fmx] - com.er.nm.if.ist.NoMatchingUpgradeClauseFoundException: 
--------------------------< END 2008-04-08 03:22:51 >------------------

The output should be:

HTML Code:

---------< FM(fm_core,fmba,fmaa,fmx,fmav) 2008-04-08 03:14:09 >-------
[main] Error installing feature [fmx] - com.er.nm.if.ist.NoMatchingUpgradeClauseFoundException:

I'm not familiar with awk command, and if you can guide me on this please?
Any help is greatly appreciated.

//racbern

aju_kup · #2 (**permalink**) 04-23-2008

try this

#! /usr/bin/ksh

cat linebetween.d | awk '
/EXECUTE/ { start = 1; nextline=1; continue }
/END/ { start = 0 ; continue}
(/Error/ || /failed/ || /error/ || /warning/) && start == 1 { print hesderline; print $0 }
{ if (nextline == 1 ) {hesderline = $0; nextline=0}}
'

racbern · #3 (**permalink**) 04-23-2008

Hi aju_kup,

Thanks for your quick reply.

I tried your suggestion, and it only prints the lines with the patterns "Error|failed|error|warning". I need to get also the line above it.

I did some trial and error of the awk command and come out with the following (but I dont know how to get the line above it):

# awk '/EXECUTE/,/END/ { if ($0 ~ /Error installing/) print $0}' /var/tmp/llsva.log

//racbern

aju_kup · #4 (**permalink**) 04-23-2008

#! /usr/bin/ksh

cat linebetween.d | awk '
/EXECUTE/ { start = 1; continue }
/END/ { start = 0 ; continue}
(/Error/ || /failed/ || /error/ || /warning/) && start == 1 { print pline; print $0 }
{ pline = $0}
'

racbern · #5 (**permalink**) 04-23-2008

Hi aju kup,

Thanks for your quick reply.

Can you explain me the code as well please?

//racbern

era · #6 (**permalink**) 04-23-2008

The cat is useless, of course, and you can combine all those search expressions into one big ole regular expression:

Code:

awk '/EXECUTE/ { start = 1; continue }
/END/ { start = 0; continue }
start && /[Ee]rror|failed|warning/ { print pline; print }
{ pline = $0 }' file

The essential point is that pline captures the previous line when it wasn't printed; and start is true when you have seen an EXECUTE but not yet an END. So when start is true and the regular expression matches, you print the previous line and the current line.

racbern · #7 (**permalink**) 04-23-2008

Hi era,

Thanks for reply as well.
I added == 1 on your suggestion, and it worked fine as well.

awk '/EXECUTE/ { start = 1; continue }
/END/ { start = 0; continue }
start == 1 && /[Ee]rror|failed|warning/ { print pline; print }
{ pline = $0 }' file

Is there a way I can assign the pline to a variable, so that I can manipulate it afterwards?

Thanks again..

//racbern

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