Quote:

Originally Posted by aravindc Hi, I'm trying the following: Code: code_0_0=1001 code_0_1=Test1 code_1_0=1002 code_1_1=Test1 x=1001 while [ $i -le 1 && $x -ne $code_$i_0 ] do i=`expr i + 1` done echo The Value Matched at $i variable and has value $code_$i_1 Please let me know where the problem in above code

First, you haven't initialized $i.

Then, there are two problems in the test statement. The first is the attempt to use an indirect variable.

If you are using bash, you can build the name of the variable and use the ! expansion:

Code:

iv=code_${i}_0
val=${!iv}

For other shells (and for portability), use eval:

Code:

eval "val=\$code_${i}_0"

In both of the above examples, note the braces around the 'i' to prevent the variable being interpreted as $i_0.

You cannot use && inside a test expression; either use -a or two separate test commands:

Code:

while [ $i -le 1 -a $x -ne $val ]

Or:

Code:

while [ $i -le 1 ] && [ $x -ne $val ]