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04-16-2008
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regex test in bash
Hi
I want to do a regex test and branch based on the test result, but this doesn't seems to work  if [[ $lastele =~ \([0-9]\) ]] then echo success else echo failed fi |
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04-16-2008
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You shouldn't backslash-escape the parentheses. But if your regular expression is that simple, you could also use case instead. Code:
case $lastele in *[0-9]*) echo success;; *) echo failed >&2 esac |
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