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04-15-2008
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doubt in awk
Hi ,
I have a file in the below format: 1.txt awk 'BEGIN { printf ("%1s", "man" )} ' awk 'BEGIN { printf ("%9s", "women" )} ' awk 'BEGIN { printf ("%56s", "human")} ' ## ### ## echo "$!" ## awk 'BEGIN { printf ("%1s", "aaa" )} ' awk 'BEGIN { printf ("%19s", "bbb" )} ' awk 'BEGIN { printf ("%24s", "ccc" )} ' ### # ## awk 'BEGIN { printf ("%1s", "rrr"} ' awk 'BEGIN { printf ("%31s", "ddd"}' awk 'BEGIN { printf ("%43s","eeee"}' I want to convert it to the below file: 2.txt awk 'BEGIN { printf ("%1s", "man" ); printf ("%9s", "women" ); printf ("%56s", "human")}' ## ### ## echo "$!" ## awk 'BEGIN { printf ("%1s", "aaa"); printf ("%19s", "bbb"); printf ("%24s","ccc" )}' ### # ## awk 'BEGIN { printf ("%1s", "rrr"); printf ("%19s", "ddd"); printf ("%24s","eeee")}' Can this be done? Thanks in advance JS 
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04-15-2008
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Code:
awk -v sq="'" -F "[}{]" '
/^awk/ && n == 0 { print "awk", sq, "BEGIN {" }
/^awk/ { print $2; n = 1 }
n == 1 && ! /^awk/ { n = 0; print "}" sq }
! /^#/ { print }
END { print "}" sq }
' "$FILE"
#
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04-15-2008
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Hi Johnson ,
I got the out as below : awk ' BEGIN { printf ("%1s", "man" ) awk 'BEGIN { printf ("%1s", "man" )} ' printf ("%9s", "women" ) awk 'BEGIN { printf ("%9s", "women" )} ' printf ("%56s", "human") awk 'BEGIN { printf ("%56s", "human")} ' }' echo "$!" awk ' BEGIN { printf ("%1s", "aaa" ) awk 'BEGIN { printf ("%1s", "aaa" )} ' printf ("%19s", "bbb" ) awk 'BEGIN { printf ("%19s", "bbb" )} ' printf ("%24s", "ccc" ) awk 'BEGIN { printf ("%24s", "ccc" )} ' }' echo "$!" awk ' BEGIN { printf ("%1s", "rrr") awk 'BEGIN { printf ("%1s", "rrr")} ' printf ("%31s", "ddd") awk 'BEGIN { printf ("%31s", "ddd")}' printf ("%43s","eeee") awk 'BEGIN { printf ("%43s","eeee")}' }' }' Am trying to tune the code a bit so tat I can reach to the required o/p Thanks a lot for ur time JS
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04-16-2008
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This puts the closing quote on a separate line, maybe that's acceptable?
Code:
awk -v sq="'" '
{ if (/^awk .BEGIN { /){
if (prev) gsub("awk " sq "BEGIN", "");
gsub ("} *" sq, "}");
prev = 1;
} else {
if (prev) printf ("%c\n", sq);
prev = 0;
}
print }
END { if (prev) printf "%c\n", sq }' 1.txt
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