awk how to print if the search pattern contains speace

McLan · #1 (**permalink**) 04-09-2008

the data file is as below:

HTML Code:

> cat master.cnf
/usr| location for usr|5
/src/ver1| version 1 |10
/src/ver2/log| ver 2 log |25
/src/sys/apps/log| Application log for sys|36
/src/sys/apps/conf| configuration location for app|45
/src/sys/apps/bin| binary location app|55my script is as below:

Code:

>desc='Application log for sys'
>echo $desc
Application log for sys
> awk -F '|' -v var=$desc '$0 ~ var{print $3}' master.cnf

Quote:

output is
input file "for"input file "sys"input file "$0 ~ var{print $3}"
/usr| location for usr|5
/src/ver1| version 1 |10
/src/ver2/log| ver 2 log |25
/src/sys/apps/log| Application log for sys|36
/src/sys/apps/conf| configuration location for app|45
/src/sys/apps/bin| binary location app|55Quote:

Quote:

I need to print field 3 separated by "|" and I want to use varibale to seach , the value of variable can contin the space char.
Please suggest me

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