how to List out the Files based on the file Size...?

psiva_arul · #1 (**permalink**) 04-08-2008

Hi all,

i want to list put the files from one Directory order by size of the files order by ascending order.

i have written the simple command to list out the file name and file size, but its not listing as in ascending order.

ls -l|awk '{print $9 $5}'

output is Dir_files.ksh1108
FilesSize.ksh 241
LFiles.txt 64
Lfiles.txt 1340
List.txt 93
NoLines.ksh 73
PTH 50
add.ksh 202
ctl_name.log 226

So,Please guide me how to list out the files and file size in ascending order

Regards,
Siva.P
Bangalore

fpmurphy · #2 (**permalink**) 04-08-2008

Here is one way ...

Code:

 ls -l | sort +4rn |awk '{print $9, $5}'

helper · #3 (**permalink**) 04-08-2008

du -sk * |sort -nr

This will do the need.

ShawnMilo · #4 (**permalink**) 04-08-2008

Simple -- use the -S flag on ls...

use -rS to print the largest last.

ghostdog74 · #5 (**permalink**) 04-08-2008

Quote:

Originally Posted by psiva_arul

Hi all,

ls -l|awk '{print $9 $5}'

just add sort

Code:

ls -l|awk '{print $5,$9|"sort -n"}'

ShawnMilo · #6 (**permalink**) 04-08-2008

Quote:

Originally Posted by ghostdog74

just add sort

Code:

ls -l|awk '{print $5,$9|"sort -n"}'

Why are people still posting?

The ls command has a -S flag which does this. Or -Sr to reverse the order. Problem solved, and there is no better way possible. It's built in!

ghostdog74 · #7 (**permalink**) 04-08-2008

Quote:

Originally Posted by ShawnMilo

Why are people still posting?

because i feel like it?

Quote:

The ls command has a -S flag which does this. Or -Sr to reverse the order. Problem solved, and there is no better way possible. It's built in!

not every ls has -S, but most *nix have sort (and du )

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