Perl: Match a line with multiple search patterns

Juha · #1 (**permalink**) 04-07-2008

Hi

I'm not very good with the serach patterns and I'd need a sample how to find a line that has multiple patterns.

Say I want to find a line that has "abd", "123" and "QWERTY" and there can be any characters or numbers between the serach patterns, I have a file that has thousands of lines and each of them can contain one or two of above patterns.

What I want is to print out a line that has all those 3 search patterns.

Thanks,
//Juha

danmero · #2 (**permalink**) 04-07-2008

Code:

awk '/123/ && /abd/ && /QWERTY/{print}'  file

KevinADC · #3 (**permalink**) 04-08-2008

It is not clear if you need to check for all the patterns or any of the patterns:

All of them:

Code:

if (/123/ && /abd/ && /QWERTY/) {
    found all patterns
}

any of them:

Code:

if (/123/ ||  /abd/ || /QWERTY/) {
    found one or more patterns
}

Juha · #4 (**permalink**) 04-08-2008

Thanks danmero and KevinADC!

I took the example from KevinADC as I'm trying to get on top of perl scripting

danmero · #5 (**permalink**) 04-08-2008

Quote:

Originally Posted by KevinADC

It is not clear if you need to check for all the patterns or any of the patterns:

Look like the OP ask for all patterns on the same line

Quote:

Originally Posted by Juha

....I want to find a line that has "abd", "123" and "QWERTY" and there can be any characters or numbers between the serach patterns...

KevinADC · #6 (**permalink**) 04-08-2008

Quote:

Originally Posted by danmero

Look like the OP ask for all patterns on the same line

Yes, but the next sentence makes that ambiguous (to me anyway):

Quote:

I have a file that has thousands of lines and each of them can contain one or two of above patterns.

Juha · #7 (**permalink**) 04-08-2008

ok.. Let me clarify a little:

Originally I wanted to print a line only if ALL the patterns can be found from that line, so this was ok:

Code:

if (/123/ && /abd/ && /QWERTY/) {
    found all patterns
}

Now, I found a different scenario, which I've tried to figure out... but have to admit that could not..

I'd like to print the line only if I can find "123" and abc", but not "efg":

I thought maybe I could use:

Code:

if (/123/ && /abc/ !& /efg/) {
    found all patterns
}

But !& does not seem to be a valid operator... What would be a way around it?

Thanks.. and sorry for being a bit unclear..

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