can you solve this code :

satyam_sat · #1 (**permalink**) 04-02-2008

I have the below fixed file ..... and the sample code to convert csv ...last week it was working good ....to day i face error ....can you solve ...
Note : Iam passing ending positions as variables .... 4 ,5,15 etc....

source.txt :

E116015/29/19930E001E000
E122012/23/19940E001E003
E104012/04/19940E001E003

sed -e 's/./&,/4' 's/./&,/5' 's/./&,/15' 's/./&,/16' 's/./&,/20' 's/./&,/24' source.txt > delimited.csv

delimited.csv :

E116,0,15/29/1993,0,E001,E000
E122,0,12/23/1994,0,E001,E003
E104,0,12/04/1994,0,E001,E003

KevinADC · #2 (**permalink**) 04-02-2008

Well, whats the error? Or is this some type of guessing game?

satyam_sat · #3 (**permalink**) 04-02-2008

sorry ,

I got the following error :

sed: can't read s/./&,/5: No such file or directory
sed: can't read s/./&,/15: No such file or directory
sed: can't read s/./&,/16: No such file or directory
sed: can't read s/./&,/20: No such file or directory
sed: can't read s/./&,/24: No such file or directory

Franklin52 · #4 (**permalink**) 04-02-2008

Double posting questions is against the:

Simple rules of the UNIX.COM forums:

Please continu here:

how to convert Fixed length file to delimited file.

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