shell script to find and copy the files creted in the year 2006 to another directory

manas6 · #1 (**permalink**) 04-01-2008

Hi All,

I am new to UNIX. I will be thankful if some one helps me.
I have to write a shell script for one of the requirement.

I have files created from Jan 2006 to March 2008.
My requirement is to write a script in such a way that
1) To find and copy(not Moving) the files created in the year 2006 to another directory(xyz). The shell should automatically create the directory in the currect path.
2) Then the compress the folder(xyz), which contains all the files created in the year 2006.

Thanks in advance.

Regards
manas

era · #2 (**permalink**) 04-01-2008

The regular solution would be find but it's a bit unwieldy, and it is better at relative age (more than 1 year old, etc) than at finding all files from a particular year. I would whip up a quick Perl script for finding the files; the rest should be trivial enough to leave as an exercise for you.

Code:

perl -e 'for $file (<*>) {
  next unless -f $file;
  my @s = stat($file);
  my @d = localtime($s[10]);
  print "$file\n" if $d[5] == 106; } # 1900 + 206 = 2006'

ghostdog74 · #3 (**permalink**) 04-01-2008

Code:

ls -l | awk '$8==2006{print $NF}' | xargs -i cp "{}" /destination

works on the current directory only. I leave the rest to you.

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