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#1
03-28-2008
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[bash] Check if variable is set or blank
Hello guys. In my script, i have the following code: Code:
echo "The tarfile contains these directorys"
tar -tf file.tar > tarlist.txt
cat tarlist | awk -F/ '{print $1 "/" $2}' | nl
echo "Enter path of the directory you want to extract or just press enter to extract everything: "
read path
/usr/local/bin/gtar -xf file.tar $pathI need to check if the user gave a path to the script, or if he just pressed enter? I know what to do between the 'THEN' and 'ELSE' statements. I just need to know how to check if $path is really set or not. |
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#2
03-28-2008
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Code:
case $path in '') echo not set;; *) echo is set;; esac If you want to distinguish between not set and set but empty, have a look at the ${var-value} and ${var:-value} construct. As long as you are not quoting $path, you don't need to make things conditional, though.. Your code should work already. (On the other hand, you properly ought to put $path in double quotes.) PS. You are extracting into tarlist.txt, but using tarlist without the .txt. Also the cat | awk is a Useless Use of Cat. Google for that phrase. Last edited by era; 03-28-2008 at 09:44 AM.. Reason: P.S. |
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