diaplaying the grep result

rag84dec · #1 (**permalink**) 03-27-2008

Hi,
My code is like this

Code:

if swlist -a revision 2>/dev/null | grep ABC 2>/dev/null  
then
		
     echo "Found  Above mentioned ABC Version, please remove it first..." 
fi

This is displaying the result to the screen.

i want to first suppress that and for that i wrote the below code

Code:

if swlist -a revision 2>/dev/null | grep ABC 2>/dev/null  > /dev/null
then
	$temp=swlist -a revision 2>/dev/null | grep ABC 2>/dev/null  	
     echo "Found  $temp ABC Version, please remove it first..." 
fi

But it is not working .... can any one help me???

Thanks

era · #2 (**permalink**) 03-27-2008

The syntax of the assignment is all wrong. But you can avoid running the thing twice. This is one of the few situations where really you want to execute a command first, and then examine its exit code in $?

Code:

temp=`swlist -a revision 2>/dev/null | grep ABC` # note backticks, not regular quotes
case $? in 0) # grep succeeded, meaning it was found
    echo Found $temp ABC version, please remove it first ... >&2 ;;
esac

I took the liberty of removing the 2>/dev/null from grep, because I don't see how it could produce an error.

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