Trying to implement case - Shell Programming and Scripting

ssunda6 · #1 (**permalink**) 03-21-2008

Hi All,

My requirement is if the record is starting with 0, then do some processing.
if starting with 1, some processing
else (not with 0 or 1 ) then do some other processing.

i tried the following

Code:

case "$test" in
/^0/) echo "starting with zero ;;
/^1/) echo " with one" ;;
*) echo "otherwise"
esac

Though the record is starting with zero, it is printing "otherwise" everytime.

Tried implementing throuh awk also.

Code:

echo $test | awk '
/^0/ { print "starting with zero" }
/^1/ { print "with 1" }
'

But I am unable to figure out how to tell awk to do something whenever both the patterns are not matched.
Please provide inputs.
Regards.

fpmurphy · #2 (**permalink**) 03-21-2008

Here is a short example:

Code:

#!/usr/bin/ksh93

test="01234"

print "test=$test"

case ${test} in
0*)  print "started with zero";;
1*)  print "started with one";;
*)   print "otherwise";;
esac

exit 0

ssunda6 · #3 (**permalink**) 03-21-2008

Hi

Thanks a lot. It is working.
Missed a simple logic.

Regards.

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