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03-19-2008
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Remove last character of a term
Hi All,
I have a few terms with a comma as the last character. Can any experts show me how to remove the last character? Note the the length of the term is not fix. Input: 1, 2, 12, 14, 103, 198, 3006, Output, 1 2 12 14 103 198 3006 |
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03-19-2008
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Some possibilities:
Code:
cut -d"," -f1 Code:
sed '/,$//' Code:
awk -F, '{print $1}'
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03-19-2008
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Hi, Raynon -
Two easy ways, asusming you're using a file: 1. awk -F',' '{print $1}' infile > outfile 2. cut -d',' -f1 infile > outfile I've quoted the comma delimiter in both cases to demonstrate that you should use quotes if the delimiting character could possibly be interpreted by the shell (such as $ or *). Hope this helps, John |
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03-19-2008
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Thks John and Frankin,
They worked jus fine. !!! Cool!! Just a small problem, how can i incorporate above " awk -F',' '{print $1}' " to the below code to the statement in blue?? I am expecting my 3rd field to be smiliar to for eg " 15, " but i only want to capture " 15 ". Can you help ? Code:
$1 == "Device" && $2 == "id" {
#print;
unit_no = $3;
flag = 1}
flag > 0 && flag < 4 && $9 == "Device" && $10 == "Sort" {
print flag;
printf ("%s %s\n",unit_no,$0)
flag++;
}
flag > 3 {flag = 0}
Last edited by Raynon; 03-19-2008 at 11:02 AM.. |
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03-19-2008
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Quote:
Code:
unit_no=$(echo $3 | awk '{print substr($0,1,match($0,/\,/)-1)}')
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03-19-2008
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Place this command before the code in blue to remove the comma:
Code:
sub(",","",$3)
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03-20-2008
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Quote:
Hi Franklin, Thks that's clean. |
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