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03-15-2008
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bash awk codes to perl
Hi,
I am interesting in writing the following bash codes into perl My script is simple take field 2 in /etc/passwd and put into an array #!/bin/bash PASSWD_FILE=/etc/passwd A=(`awk -F: ' { print $2 }' $PASSWD_FILE `) Can someone give me equivalent codes in perl ? |
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03-15-2008
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how about trying it out
1) read the file line by line using while loop 2) split the line by ":" as delimiter 3) get the second element using array indices. |
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