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03-04-2008
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Merging lines using AWK
Hi,
Anybody help on this.  I want to merge the line with previous line, if the line starts with 7. Otherwise No change in the line. Example file aa.txt is like below 122122 222222 333333 734834 702923 389898 790909 712345 999999 My output should be written in another file called bb.txt 122122 222222 333333734834702923 389898790909712345 999999 Your help is very much appriciated. Last edited by senthil_is; 03-04-2008 at 11:19 PM.. Reason: change |
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03-05-2008
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Code:
awk 'BEGIN{t=""}
{
if ($1 ~ /^7/)
t=sprintf("%s%s",t,$1)
else
t=sprintf("%s\n%s",t,$1)
}
END{
print t
}' filename
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03-05-2008
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 Thanks summer.The output is coming with one blank line in the header. # Here blank line is coming. 122122 222222 333333734834702923 389898790909712345 999999 How to avoid and how to redirect to another file. |
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03-05-2008
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One way:
Code:
awk '
NR>1 && substr($0,1,1)!=7{printf("\n")}
{printf("%s",$0)}
END{if(substr($0,1,1)!=7){printf("\n")}}
' file
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03-05-2008
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Did you want an extra blank line at the end of the file? If not
Code:
awk '$0=(NR>1&&!/^7/)?RS$0:$0' ORS= file |
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03-05-2008
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Quote:
Code:
[n]awk '{
if ($0 ~ /^7/)
l = l" "$0
else {
if (l) print l
l = $0
}
} END {if (l) print l}' aa.txt > bb.txt
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