converting hex to dec

aismann · #1 (**permalink**) 02-26-2008

Hi Experts,

I have a file called "hex" which contains info like below

Quote:

0x0DD
0x1E9
0x1EA
0x1EB
0x1F4
0x1F7
0x1F9
0x1FE
0x202
0x203
0x208
0x209
0x20E
0x20F
0x210

How do i convert everything in this file to decimal value? Please advice. Thanks

Franklin52 · #2 (**permalink**) 02-26-2008

One solution:

Code:

cat hex | while read value
do
 printf "%d\n" $value
done

Regards

aismann · #3 (**permalink**) 02-26-2008

Hi Franklin,

This is what i get

Quote:

root@ckpgpay11core> cat hex| while read value; do printf "%d\n" $value; done
bash: printf: 0x0DD: illegal number
bash: printf: 0x0DE: illegal number
bash: printf: 0x0E1: illegal number
bash: printf: 0x0E2: illegal number
bash: printf: 0x0E3: illegal number
bash: printf: 0x0E4: illegal number
bash: printf: 0x0E5: illegal number
bash: printf: 0x0E6: illegal number
bash: printf: 0x0E7: illegal number
bash: printf: 0x0E8: illegal number
bash: printf: 0x0F2: illegal number
bash: printf: 0x1A4: illegal number
bash: printf: 0x1B8: illegal number
bash: printf: 0x1B9: illegal number
bash: printf: 0x1BA: illegal number
bash: printf: 0x1BB: illegal number

aismann · #4 (**permalink**) 02-26-2008

even after removing the "0x"

Quote:

root@ckpgpay11core> cat sara2 | while read value; do printf "%d\n" $value; done
bash: printf: 0DD: illegal number
bash: printf: 0DE: illegal number
bash: printf: 0E1: illegal number
bash: printf: 0E2: illegal number
bash: printf: 0E3: illegal number
bash: printf: 0E4: illegal number
bash: printf: 0E5: illegal number
bash: printf: 0E6: illegal number
bash: printf: 0E7: illegal number
bash: printf: 0E8: illegal number
bash: printf: 0F2: illegal number
bash: printf: 1A4: illegal number

chella · #5 (**permalink**) 02-26-2008

Hi,

Use typeset command in UNIX to do the conversion. I think you need to used typeset -i. Try typeset after removing '0x'.

Regards,
Chella

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