subtracting Tue, Feb 26, 2008 01:38:25 AM from Mon, Feb 25, 2008 09:30:03 PM

#1 (**permalink**) 02-26-2008

Hi,

Please help me out in creating a script which will subtract Tue, Feb 26, 2008 01:38:25 AM from Mon, Feb 25, 2008 09:30:03 PM and will give me out put in the format hh:mm:ss.

I tried datecalc.It doesnt work for this format.

jaduks · #2 (**permalink**) 02-26-2008

Code:

$ cat datediff.sh
#!/bin/sh

D1=`date +%s -d "Feb 26, 2008 01:38:25 AM"`
D2=`date +%s -d "Feb 25, 2008 09:30:03 PM"`
((diff_sec=D1-D2))
echo - | awk '{printf "%d:%d:%d","'"$diff_sec"'"/(60*60),"'"$diff_sec"'"%(60*60)/60,"'"$diff_sec"'"%60}'

$ sh datediff.sh
4:8:22

//Jadu

#3 (**permalink**) 02-27-2008

The script is giving the error:

Quote:

date: bad format character - s
date: bad format character - s
./datediff.sh[5]: diff_sec=D1-D2: bad number

please help!!

vino · #4 (**permalink**) 02-27-2008

I thought you said the problem was solved. See Time Between Dates - The UNIX Forums

Please do not open multiple threads for the same problem. You already have opened 3 other threads. Break the rule once more and you will earn a temporary ban.

#5 (**permalink**) 02-27-2008

The problem is not yet solved.
The output I require is in hh:mm:ss and dateclac doesn't provide me.

jaduks · #6 (**permalink**) 02-27-2008

First check whether you can see the epoch time for the below command:

Code:

$ date +%s -d "Feb 26, 2008 01:38:25 AM"
1203970105

And if that is successful, then

try

Code:

diff_sec=`expr $D1 - $D2`

instead of

Code:

((diff_sec=D1-D2))

For me the script I gave above works.

manikantants · #7 (**permalink**) 02-27-2008

Quote:

Originally Posted by Sreejith_VK

I tried datecalc.It doesnt work for this format.

Convert your date to the required format which datecalc expects and pass it.

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