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Date parsing into string, help! Date parsing into string, help!
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  #1 (permalink)  
Old 02-17-2008
martyb555 martyb555 is offline
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Date parsing into string, help!
I have a file that was created yesterday that I want to access...
daily.log2008-02-16

I am using...
curr_time=`date +"%Y %m %d"`
yesterday=`./datecalc.ksh -a $curr_time - 1`

the value for yesterday is now "2008 2 16"

in ksh, how do I transform the string "2008 2 16" into "2008-02-16"
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Old 02-17-2008
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Tytalus Tytalus is offline Forum Advisor  
echo {1..9}^2\;|bc
  
 

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Code:
printf "%d-%02ld-%d" 2008 2 16
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Old 02-17-2008
Tytalus's Avatar
Tytalus Tytalus is offline Forum Advisor  
echo {1..9}^2\;|bc
  
 

Join Date: Jun 2003
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i.e. same sort of thing as:

Code:
echo "2008 2 16" | awk '{printf("%d-%02ld-%d",$1,$2,$3)}'
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Old 02-17-2008
danmero danmero is offline Forum Advisor  
丹
  
 

Join Date: Nov 2007
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Everything in one line:

Code:
yesterday=`./datecalc.ksh -a $curr_time - 1 | awk '{print $1"-"$2"-"$3}'`
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Old 02-17-2008
martyb555 martyb555 is offline
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THANK YOU for your help
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Old 02-17-2008
ghostdog74 ghostdog74 is offline Forum Advisor  
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Code:
# echo "2008 2 16" | tr ' ' '-'
2008-2-16
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