i have a ksh script :

#!/bin/ksh
TZ=`date +%Z`+24 ;a=`date +%Y-%m-%d`

b=`date +"%H:%M:%S"`
cd /ednadtu3/u01/pipe/logs
for i in Archiver1.log
do

cat $i | grep $a | grep $b >> /ednadtu3/u01/pipe/naveed/Insert_Date.txt
done
------------------------------------------------------------------

here i want to grep certain given values of hour in file Archiver1.log.
but this script greps current time of system. i want to grep 20th hour in file Archiver1.log. how to do that.

actually i want to insert the own values in below format

b=`date +"%H:%M:%S"`

------------------------------

What does the data look like?

something like this what your looking for (obviously cleaned up to only match the date area of the log versus the content portion.

the data looks like

2008-02-11 20:23:34
2008-02-11 20:53:20
2008-02-11 20:25:44


2008-02-11 21:40:34

2008-02-11 23:59:00

----------------------------------------------------------------------

i want to grep only 20th hour. thanks ur suggestion helped me. now i m able to grep . thanks dude

So this (very cut and paste, you could easily shorten)

Since you have the -E flag