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02-02-2008
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Sed Question?
Hi,
Here's what I'm trying to do. I have a set of numbers like this: 12-13 15-18 23-28 36-38 42-43 53-56 70-72 76 80-86 93-110 119-128 But I want to echo the ranges of numbers. Is there any way I can get sed to replace for example, "12-13 15-18" with "{12..13} {15..18}" so it will echo the entire range? Or, is there a better way of accomplishing this? Thanks! 
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02-02-2008
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I'm not really a sed coder but I think it is the same as perl in this situation with the excpetion that sed does inplace editing by default (I could be wrong). The problem is you have not described your input besides saying it has those sequence of ranges you posted.
Code:
sed -e 's/([0-9]+)(-)([0-9]+)/{\1..\2}/g' file
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02-02-2008
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KevinADC,
Thanks for looking into it. I tried it and got this error: sed: -e expression #1, char 32: invalid reference \2 on `s' command's RHS Is there anymore info I can give you to make my situation more clear? Thanks again.
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02-02-2008
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Hi.
The seds I have used do not do "in-place" processing by default. If they allow it, it's usually with the "-i" option. If your sed allows "-r", here's one way: Code:
#!/bin/bash -
# @(#) s1 Demonstrate sed extended regular expression match, substitution.
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version =o $(_eat $0 $1) sed
FILE=${1-data1}
echo
echo " Input file $FILE:"
cat $FILE
echo
echo " As processed by sed:"
sed -r -e 's/([0-9]+)-([0-9]+)[ ]*/{\1..\2} /g' $FILE
exit 0
Code:
% ./s1
(Versions displayed with local utility "version")
Linux 2.6.11-x1
GNU bash 2.05b.0
GNU sed version 4.1.2
Input file data1:
12-13 15-18 23-28 36-38 42-43 53-56 70-72 76 80-86 93-110 119-128
As processed by sed:
{12..13} {15..18} {23..28} {36..38} {42..43} {53..56} {70..72} 76 {80..86} {93..110} {119..128}
Last edited by drl; 02-02-2008 at 04:01 PM. Reason: Spelling mistake.
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02-02-2008
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Hi.
If you are stuck with a sed that does not recognize "-r" such as on Solaris, you can use: Code:
#!/bin/bash -
# @(#) s1 Demonstrate sed extended regular expression match, substitution.
SED=/usr/xpg4/bin/sed
SED=sed
echo "(Versions displayed with local utility \"version\")"
# version >/dev/null 2>&1 && version =o $(_eat $0 $1) $SED
uname -rs
version >/dev/null 2>&1 && version bash $SED
FILE=${1-data1}
echo
echo " Input file $FILE:"
cat $FILE
echo
echo " As processed by sed:"
# $SED -r -e 's/([0-9]+)-([0-9]+)[ ]*/{\1..\2} /g' $FILE
$SED -e 's/\([0-9][0-9]*\)-\([0-9][0-9]*\)[ ]*/{\1..\2} /g' $FILE
exit 0
Code:
$ ./s1
(Versions displayed with local utility "version")
SunOS 5.10
GNU bash 3.00.16
sed (local) - no version provided.
Input file data1:
12-13 15-18 23-28 36-38 42-43 53-56 70-72 76 80-86 93-110 119-128
As processed by sed:
{12..13} {15..18} {23..28} {36..38} {42..43} {53..56} {70..72} 76 {80..86} {93..110} {119..128}
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02-02-2008
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Quote:
Code:
sed 's/\([0-9][0-9]*\)-\([0-9][0-9]*\)/{\1..\2}/g' file
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