using && in if statement .. - Shell Programming and Scripting

jisha · #1 (**permalink**) 02-01-2008

Hi All,

Can some one tell me how to get run the following:

data1="hello"
data2="world"
if [ "$data2" != "world" && "$data1" != "hello"]
then
{
echo "good afternnon"
}
else
{
echo " good morning"
}
fi

The above code gives me an error ad below :
./if.h: line 3: [: missing `]'

Thanks in advance
Js

panknil · #2 (**permalink**) 02-01-2008

Dear jisha,

try this

data1="hello"
data2="world"
if [ "$data2" != "world" ]
then
if [ "$data1" != "hello" ]
then
echo "good afternnon"
fi
else

echo " good morning"
fi

Regards,
Pankaj

Tytalus · #3 (**permalink**) 02-01-2008

try:

Code:

if [ "$data2" != "world" ] && [ "$data1" != "hello" ]

V3l0 · #4 (**permalink**) 02-01-2008

Don't forget to let a space before ] and after [ !
Here is the code :

Code:

data1="hello"
data2="world"
if [ "$data2" != "world" ] && [ "$data1" != "hello" ]
then
{
        echo "good afternnon"
}
else
{
        echo " good morning"
}
fi

manas_ranjan · #5 (**permalink**) 02-01-2008

which code is this ???? shell script ?????

jisha · #6 (**permalink**) 02-01-2008

Thanks to all !!

Its working now.. I did a lot of debugging still i didnot get ...I think the problem was with the spacing

Thank you so much

Js

fpmurphy · #7 (**permalink**) 02-01-2008

If you want to make your schell script more efficient you should use the shell builtins

Code:

#!/usr/bin/ksh

data1="hello"
data2="world"

if [[ "$data2" != "world" && "$data1" != "hello" ]]
then
    print "good afternnon"
else
    print "good morning"
fi

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