printing the next line too?? - Shell Programming and Scripting

AndyA · #1 01-30-2008

Hi, I'm trying to get awk to print every line ending with a colon along with the next line. I have a file like:

Blah Blah a bunch of words, the money things are as follows:
Spokane 340,087, 000 3.24500% January 23, 2008

does anyone have any advice on this matter? I'm a bit stumped...

Thanks

AndyA · #2 01-30-2008

I forgot to mention that I only want to print the next line if it contains numbers.

Thanks again.

summer_cherry · #3 01-30-2008

Hi
Try follow code:

input:

Code:

This is the first line
This is the second line:
This is the third line
This is the forth line:
This is the fifth line
This is the last line

output:

Code:

This is the second line:
This is the third line
This is the forth line:
This is the fifth line

code:

Code:

nawk '
/:$/{
print
getline
print
}' filename

ghostdog74 · #4 01-30-2008

Code:

awk '/:$/{f=1;print;next}f{print;exit}' file

jaduks · #5 01-30-2008

A SED version of the same

Code:

$ sed -n '/:$/{p;n;p;}' lines.out

//Jadu

Yogesh Sawant · #6 01-31-2008

Quote:

Originally Posted by jaduks

A SED version of the same

Code:

$ sed -n '/:$/{p;n;p;}' lines.out

//Jadu

or better yet:

Code:

sed -n '/:$/ {N; /[0-9]/ p;}' file

thana · #7 01-31-2008

I think the second line should be printed if it contains a digit, not the every second line

eg
cat filename

one two three:
1 2 3
four five six
4 5 6

the o/p should be

one two three:
1 2 3

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