print out result from data file - Shell Programming and Scripting

thms_sum · #1 01-30-2008

i got a data file which contains all the pid,ppid,user,command,pcpu,start_time,status. I wanted to display out the pcpu which is greater than 0.

i uses awk'{if($5 > 0){print}}' filename.txt but is printing out result which not i wanted. Is there any way which i can print out those pcpu which is greater than 0?

jaduks · #2 01-30-2008

Both of them should work

Code:

awk '{if($5 > 0){print}}' file
awk '$5 > 0 {print}' file

Could you please put some sample data of your file.

panknil · #3 01-30-2008

Dear thms sum,

can u plz provide an example of ur need?

regards,
Pankaj

thms_sum · #4 01-30-2008

i have attached a sample of my data file. i would like to only display cpu which is above 0 from the data file. how can go with awk to make it display?

radoulov · #5 01-30-2008

Code:

awk '$(NF-2)>0' input

thms_sum · #6 01-30-2008

thanks radoulov!!! its works!!! but can u explain y got to NF-2?

radoulov · #7 01-30-2008

Some CMD column values contain spaces so for Awk (with default FS) %CPU is not always $5,
therefore as long as START and STAT values don't contain spaces $(NF-2)
(the number of fields of the crrent record - 2) will work

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