Hi,

Pls can some one help.
Need a script which will read a command line $1 which is a date,

then based on the date in $1 calc next day or previous day etc and output the result in YYYYMMDD format.

e.g abc.sh 01/01/2008

output required is
01/01/2008 + 1day = 01/02/2008
or
01/01/2008 + 3days = 01/04/2008

is it possible using
mydate=date -d "$1" +%m%d%y
j="$mydate" -d "next day" +%m%d%y (this does not work)

Thks in adv..

Okay. IF you will look in the Unix Forums FAQ, you will see that Perderabo wrote a script: datecalc. It is in the Date Arithmetic thread.

Cut and paste the part that does what you want.

Try this:

 date +%Y%m%d -d "yesterday"
 date +%Y%m%d -d "next day"
#-----4 days ago for ex.
date +%Y%m%d -d "4 day ago"
#-----4 days after 
date +%Y%m%d -d "4 day "

If you have perl, you could try this:

yday=`perl -e 'print scalar localtime($_) ,"\n" for time + 86400'`

Thanks for all ur inputs.

Looks like i have not state my requirement clearly.
I am aware of
date --date='next day' "+%Y%m%d" .
This will give next date of the unix system date as an output in YYYY/mm/dd format.

But what i am looking is to get the next day or next month for any date which the user is passing as a parameter.

something like this below

mydate=$1
date --date $mydate +%m%d%Y -d ýesterday (this does not work)

but i want next day or 3rd day of mydate

Is it possible ? if so pls give me the soln.

Thks