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  #1  
Old 01-25-2008
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Join Date: May 2007
Posts: 10
help required for replacing text in vi
Hi
Any one pls give me command in vi to replace /opt/usr with /home/reddy/dump .... i tried escaping / with \ bt its not working...


thanks in advance
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  #2  
Old 01-25-2008
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Join Date: Dec 2003
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At the : prompt type

Code:
#/opt/usr#/home/reddy/dump#
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  #3  
Old 01-25-2008
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Join Date: Mar 2007
Location: Somerset West, South Africa
Posts: 10
In vi:

:%s#\/opt\/usr#\/home\/reddy\/dump#g


QED! (quite easily done!)
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  #4  
Old 01-25-2008
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Join Date: Jun 2007
Location: Mumbai,India
Posts: 99
:%s_/opt/usr_/home/reddy/dump_g

u can use anydelimiter ...since ur string cntains too many slashes, therefore to avoid escaping all the slashes and messy syntex... this 1 'll be the simplest.

Anchal.
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  #5  
Old 01-25-2008
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Join Date: Jun 2007
Location: Mumbai,India
Posts: 99
@dewets : why u again esacpe the slashes... if u alreadyusing delim as "#".
i dont think its needed...
is there any other reason..... correct me if i m wrong...
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  #6  
Old 01-25-2008
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Join Date: Mar 2005
Location: Large scale systems...
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Quote:
Originally Posted by anchal_khare View Post
@dewets : why u again esacpe the slashes... if u alreadyusing delim as "#".
i dont think its needed...
is there any other reason..... correct me if i m wrong...
Yes, thats correct.

When '#' is used as delimiter no need to use '/' as '\/'

but using '#' when the patten contains '/' adds more readability
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  #7  
Old 01-26-2008
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Join Date: Jul 2007
Location: India
Posts: 14
better use perl search and replace.

Quote:
perl -i -pe 's/old pattern/new pattern/g' filename
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