need to find last character in each line in all files - Shell Programming and Scripting

dbsurf · #1 01-24-2008

Hi,

I need to read each line in all files .If last character in each line is not ;(semicolon) then i need to append next line also.Here each line may consists of multiple semicolons(

.but i need to read only last character.I need to achieve this using shell script.And i need to remove tht last semicolon also.I need to achieve this in all files in a directory and i need to redirect modified files to the same directory.
How to achieve this?

For example my file consists of
asdfgh;adffg;afdfg;
adfsffvfgggg;
aedfdsfs
fsff;

Here i need output as
asdfgh;adffg;afdfg
adfsffvfgggg
aedfdsfs fsff

How to achieve this?

Yogesh Sawant · #2 01-24-2008

if you have GNU sed:

Code:

sed -i 's/;$//' file*

or using Perl:

Code:

perl -pi -e 's/;$//' file*

dbsurf · #3 01-24-2008

quintet · #4 01-24-2008

try this

sed -e :a -e '/;$/!N;s/\n//; ta' -e 's/;$//' file

radoulov · #5 01-24-2008

Code:

awk 'ORS=/;$/?RS:FS{sub(/;$/,"")}1' filename

Use nawk or /usr/xpg4/bin/awk on Solaris.

radoulov · #6 01-24-2008

As far as the entire task is concerned:

Code:

awk 'FNR == 1 {
  system("[ -f \""fnt"\" ]&&mv "fnt" "fn)
  fn = FILENAME
  fnt = FILENAME"__"++c
}
ORS = /;$/ ? RS : FS {
  sub(/;$/,"")
  print > fnt
} END {
  system("[ -f \""fnt"\" ]&&mv "fnt" "fn)
}' filenames*

Use nawk or /usr/xpg4/bin/awk on Solaris.

dbsurf · #7 01-24-2008

Hi quintet

using this sed -e :a -e '/;$/!N;s/\n//; ta' -e 's/;$//' file its not redirecting to my directory again

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