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#1
01-24-2008
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directory tree
Hi all,
The following is a script for displaying directory tree. D=${1:-`pwd`} (cd $D; pwd) find $D -type d -print | sort | sed -e "s,^$D,,"\ -e "/^$/d"\ -e "s,[^/]*/\([^/]*\)$,\:-----\1,"\ -e "s,[^/]*/,: ,g" | more exit 0 I am trying to understand the above script.But i am not able to understand the following 2 lines -e "s,[^/]*/\([^/]*\)$,\:-----\1,"\ -e "s,[^/]*/,: ,g" | more can any body pls tell me how the above two lines works. cheers RRK 
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#2
01-24-2008
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these are sed syntex of find and replace...with regular expressions..
in first line- its searching for "/" in the begining of line for any occurance of "/". [ shown by "*"] escaped paranthesis are used to tell how many occurance.. $ used to find @ the end of every line.. \1,\2 etc used to tell where to find...
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#3
01-24-2008
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1 more thing.. [^/] means not to find "/". "^" is used to tell in the start of the line...
and if "^" used inside [] thn it treats as the negation of the exression followed by "^". hope its clear.
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#4
01-24-2008
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I did an awk tree sometime ago, maybe could be usefull for you:
Code:
find . -type d -print 2>/dev/null|awk '!/\.$/ {for (i=1;i<NF;i++){d=length($i);if ( d < 5 && i != 1 )d=5;printf("%"d"s","|")}print "---"$NF}' FS='/'
Last edited by Klashxx; 01-25-2008 at 06:52 AM. Reason: one liner optimization
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