how to get exact result in my division - Shell Programming and Scripting

user_prady · #1 01-22-2008

Hello Friends,

Why I am not getting exact result in the following division. It is rounding off automatically. Is there any way to get the exact result or
can be set by user to get how many digits to carry after the decimal.

Code:

gawk '{

  wait_ns1 = (82290 +1 )/78  # actuall result = 1055.012821
  wait_ns2 = (82320 +1 )/78  # actuall result = 1055.397436
  wait_ns3 = (82350 +1 )/78  # actuall result = 1055.782051

  print wait_ns1;
  print wait_ns2;
  print wait_ns3;

} ' my_file

output:

Code:

1055.01
1055.4
1055.78

Or How to get the actuall result ,ie,

Code:

1055.012821
1055.397436
1055.782051

Thanks in advance..

LGMENG · #2 01-22-2008

you can try this

Code:

nawk '
{
wait_ns1 = (82290 +1 )/78;
printf("%10.6f\n", wait_ns1);
}'

ghostdog74 · #3 01-22-2008

Code:

 # gawk 'BEGIN {OFMT = "%.6f"; print (82290 +1 )/78 ;}'
1055.012821

user_prady · #4 01-22-2008

Quote:

Originally Posted by LGMENG

you can try this

Code:

nawk '
{
wait_ns1 = (82290 +1 )/78;
printf("%10.6f\n", wait_ns1);
}'

Thank You BOSS..

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