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#1
01-20-2008
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grep -n lines before and after
Hi,
is it possible to grep a pattern that will include the "n" lines before and after the line where the pattern have been found? e.g. #this contains the test.file line1 line2 line3 line4 line5 then a grep command to search the word "line3" and the output should be 1 (or n) line before that line and 1 (or n) line "after" that line. dessired output of the grep command line2 line3 line4 Thanks in advance. 
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#2
01-20-2008
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If you have GNU grep, then it is possible. From man grep
Code:
-A NUM, --after-context=NUM
Print NUM lines of trailing context after matching lines.
Places a line containing -- between contiguous groups of
matches.
-B NUM, --before-context=NUM
Print NUM lines of leading context before matching lines.
Places a line containing -- between contiguous groups of
matches.
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#3
01-20-2008
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