scalar variable assignment in perl + { operator - Shell Programming and Scripting

JamesGoh · #1 (**permalink**) 01-17-2008

When reading over some perl code in a software document, I came across an assignment statement like this

$PATH = ${PROJECT}/......./....

In this particular form of scalar variable assignment, what does the curly braces operators do ? Also, what is the benefit in doing scalar assignment this way ?

many thanks

cbkihong · #2 (**permalink**) 01-17-2008

Surrounding the identifier with curly braces is more frequently seen in double-quoted strings to separate it from neighbouring text. For example,

"The time now is ${time}A.M."

This syntax also works outside strings, as you cited, but that is rarely needed and being most of the time redundant. It is there to support identifiers that start with a ^ sign, which is normally not allowed. However, I cannot think of any case that really needs to refer this kind of variables.

For more information, refer to

perlvar - perldoc.perl.org

Yogesh Sawant · #3 (**permalink**) 01-17-2008

Code:

#!/usr/bin/perl
my $cap = 53;
print "${cap}rd cap! \n";

output:

Code:

53rd cap!

JamesGoh · #4 (**permalink**) 01-20-2008

thanks guys.

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