AWK how to strip from right hand side - Shell Programming and Scripting

angelolamberti · #1 01-16-2008

guys,
i am writing a .ksh file to ssh to a remote machine and change all occurances of .ixf to .WIP like this :

-->>> for i in *.ixf do echo $i done mv $i $i.WIP exit <<---

--> this returns .ixf.WIP - i can live with that.

then i need to sftp from another remote machine, copy the files across to the new box and rename the file back to .ixf like this :

-->> for i in *.WIP; do echo $i; done; mv $i $i.ixf <<--

--> this returns .ixf.WIP.ixf - i can't live with this.

I need to strip WIP.ixf from the end, i think using awk but cannot get the syntax correct.
Any help here would be appreciated.
Thanks

n1djs · #2 01-16-2008

I assume this is a unix box...
awk is a nuclear bomb, when all you need is a hammer.

Use basename (see example below)

#!/bin/ksh
for i in *.ixf; do
name=$(basename $i .ixf)
echo $name
mv $i $name.WIP
done

zsoltika · #3 01-16-2008

If using 'sed ' is an option:

Code:

for i in *.WIP; do 
echo $i 
mv $i `echo $i | sed 's/\..*$//'`.ixf
done

Or if you want (GNU) awk, and assuming the 1st dot in the filename separates all the extension(s):

Code:

for i in *.WIP; do 
echo $i 
mv $i `echo $i | gawk -F . '{print $1}'`.ixf
done

HTH,
Zsoltik@

shamrock · #4 01-16-2008

Quote:

Originally Posted by angelolamberti

guys,
i am writing a .ksh file to ssh to a remote machine and change all occurances of .ixf to .WIP like this :

-->>> for i in *.ixf do echo $i done mv $i $i.WIP exit <<---

--> this returns .ixf.WIP - i can live with that.

then i need to sftp from another remote machine, copy the files across to the new box and rename the file back to .ixf like this :

-->> for i in *.WIP; do echo $i; done; mv $i $i.ixf <<--

--> this returns .ixf.WIP.ixf - i can't live with this.

I need to strip WIP.ixf from the end, i think using awk but cannot get the syntax correct.
Any help here would be appreciated.
Thanks

Code:

for i in *.WIP
do
  echo $i
  OUTFILE=$(echo ${i%(\.[A-Z]*)}
  mv $i $OUTFILE
done

danmero · #5 01-16-2008

Quote:

Originally Posted by zsoltika

If using 'sed ' is an option:

Code:

for i in *.WIP; do 
echo $i 
mv $i `echo $i | sed 's/\..*$//'`.ixf
done

He need to remove the extension.

Code:

for i in *.WIP
do 
  mv $i `echo $i | sed 's/\.WIP$//'`
done

angelolamberti · #6 01-17-2008

Quote:

Originally Posted by n1djs

I assume this is a unix box...
awk is a nuclear bomb, when all you need is a hammer.

Use basename (see example below)

#!/bin/ksh
for i in *.ixf; do
name=$(basename $i .ixf)
echo $name
mv $i $name.WIP
done

superb, thanks

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