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01-14-2008
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How to print a value in the variable using awk ?
 Hi All,I have a part of a script below: var1="value1" awk 'BEGIN {printf("%36s \n ","value1")}' Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement. Is this possible? If so, what is the modified awk command? Thanks in advance JS |
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