How to print a value in the variable using awk ? - Shell Programming and Scripting

jisha · #1 (**permalink**) 01-14-2008

Hi All,

I have a part of a script below:

var1="value1"
awk 'BEGIN {printf("%36s \n ","value1")}'

Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement.

Is this possible?
If so, what is the modified awk command?

Thanks in advance
JS

Klashxx · #2 (**permalink**) 01-14-2008

Same logic that the other example:

Code:

awk 'BEGIN {printf("%36s \n ","'"${var1}"'")}'

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
print variable in file using awk	kamel.seg	Shell Programming and Scripting	3	01-03-2008 02:43 AM
use variable for sed print line	atchleykl	UNIX for Dummies Questions & Answers	2	04-24-2007 09:44 AM
can awk print column using a variable ??	jambesh	Shell Programming and Scripting	36	09-26-2006 04:39 AM
print the name of variable	sun-guy	Shell Programming and Scripting	1	08-06-2006 02:03 PM
print variable in awk	kazanoova2	Shell Programming and Scripting	8	05-17-2004 03:30 PM

Thread Tools
Show Printable Version Email this Page
Display Modes
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode