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#1
01-08-2008
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cut column
I have a file as below,
$vi myfile aaa;20071217 bbb;20070404 ccc;20070254 " if I want to cut the column 9-12 of the first line , the output should be 1217 , can advise how to write a script to get the result ? thx p.s. can a script that have only ONE line could do that ? 
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#3
01-08-2008
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Quote:
Code:
cut -c 9-12 Code:
awk '{print substr($0, 9, 4)}'
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#5
01-08-2008
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Quote:
I tried it , the result is as below, 1217 0404 0254 if I only want the get the date in FIRST line , the result is 1217 , can advise how to modify the script ? thx
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#6
01-09-2008
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Code:
awk 'NR==1{print substr($0, 9, 4);exit}'
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