Could any one tell me how to do get result in fraction in shell script.

I am using expr for division of 2 number but it is giving Quitent.

I need it in full fraction value.

please helpp. how to do it using "dc" or "bc"

$echo "10/3"|bc -l
3.33333333333333333333

How to set the precision in it any gud document on net in this regard... could help me!!! and also if using in awk do this will work, if not then how to make any approach over their??

I am not sure what u want. You can user printf to print the result with desired precision.
Eg:
echo "10/3"|bc -l|xargs printf "%.2f"

In awk the syntax for printf is similar to the printf in C,C++

look up the man page of bc for a start.

Hi,

i am working very long variable.

do that way things will work???

ie 1238123781273761273/12368128273871238